If the H₂ molecule has a rotational energy of E_0r = 0.040 MeV,what is the average distance between the two atoms? A)1.0 $\times$ 10^-13 m B)3.2 $\times$ 10^-11 m C)1.0 $\times$ 10^-10 m D)1.0 $\times$ 10^-20 m E)1.4 $\times$ 10^-10 m

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The Answer of If the H₂ molecule has a rotational energy of E_0r = 0.040 MeV,what is the average distance between the two atoms? A)1.0 $\times$ 10^-13 m B)3.2 $\times$ 10^-11 m C)1.0 $\times$ 10^-10 m D)1.0 $\times$ 10^-20 m E)1.4 $\times$ 10^-10 m

If the H2 Molecule Has a Rotational Energy of E0r ×\times×

If the H₂ Molecule Has a Rotational Energy of E_0r $\times$