The effective force constant of the CO molecule is 1.86 kN/m.With 12 u for the mass of the carbon atom and 16 u for the mass of the oxygen atom,the frequency of vibration of the CO molecule is A)14.2 $\times$ 10¹³ Hz B)2.47 $\times$ 10¹³ Hz C)6.42 $\times$ 10¹³ Hz D)9.76 $\times$ 10¹³ Hz E)5.93 $\times$ 10¹³ Hz

Question

Quizplus · Accepted Answer

The frequency of vibration, in Hz, can be calculated using the following formula:

ν = (1/2π) * sqrt(k/m)

where k is the force constant and m is the reduced mass of the molecule, given by:

m = (m1 * m2) / (m1 + m2)

Substituting the given values, we get:

m = (12 * 16) / (12 + 16) = 4.8 u

ν = (1/2π) * sqrt(1.86 * 10^3 N/m / (4.8 * 1.66 * 10^-27 kg/u))

ν = 6.42 x 10^13 Hz

Therefore, the answer is C.

The Effective Force Constant of the CO Molecule Is 1 ×\times×

The Effective Force Constant of the CO Molecule Is 1 $\times$