Copper has a mass density of 8.93 g/cm³ and its molar mass is 63.55 g.If each copper atom contributes one free electron,the carrier density is A)8.46 $\times$ 10²⁸ m^-3 B)3.12 $\times$ 10²⁸ m^-3 C)4.15 $\times$ 10²⁸ m^-3 D)6.48 $\times$ 10²⁸ m^-3 E)None of these is correct.

Question

Quizplus · Accepted Answer

The carrier density (n) can be calculated using the formula:

n = ρN_A / M

where ρ is the mass density (given), N_A is Avogadro's number (6.022 × 10^23), and M is the molar mass (given).

Substituting the values, we get:

n = (8.93 g/cm3) × (6.022 × 10^23 /mol) / (63.55 g/mol)
n ≈ 8.46 × 10^22 /cm^3

Since each copper atom contributes one free electron to the carrier density, the answer is:

n ≈ 8.46 × 10^22 /cm^3.

The closest option is A).

Copper Has a Mass Density of 8 ×\times× 1028 M-3 B)3 ×\times×

Copper Has a Mass Density of 8 $\times$ 10²⁸ M^-3
B)3 $\times$