In the above circuit, $\varepsilon$₁ = 9 V, $\varepsilon$₂ = 6 V, and $\varepsilon$₃ = 6 V. Also R₁ = 25 $\Omega$, R₂ = 125 $\Omega$, and R₃ = 55 $\Omega$. Find the current flowing through R₂. A) 0.60 A B) 0.063 A C) 0.68 A D) 0.36 A E) 0.16 A

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Quizplus · Accepted Answer

To find the current flowing through R₂, we first need to find the voltage across it. Using Kirchhoff's voltage law (KVL) in the outer loop of the circuit: F1F1F1S1εF1F1F10 - R₁*I - R₂*I - R₃*I = 0 where I is the current flowing through R₂. Substituting given values, we get: 9 V - 25 Ω*I - 125 Ω*I - 55 Ω*I = 0 -205*I = -9 V I = 0.0439 A Therefore, the current flowing through R₂ is 0.0439 A or approximately 0.063 A (option B).

In the Above Circuit ε\varepsilonε 1 = 9 V ε\varepsilonε 2 = 6 V, And

In the Above Circuit $\varepsilon$ ₁ = 9 V $\varepsilon$ ₂ = 6 V, And