The index of refraction is related to the prism angle and the angle of minimum deviation by n = sin ½($\delta$ + $\phi$ )/sin ½$\phi$
The angle of minimum deviation in the figure is angle
A) 1
B) 2
C) 3
D) 4
E) 5

Question

The index of refraction is related to the prism angle and the angle of minimum deviation by n = sin ½($\delta$ + $\phi$ )/sin ½$\phi$ 
The angle of minimum deviation in the figure is angle
A) 1 
B) 2 
C) 3 
D) 4 
E) 5

Quizplus · Accepted Answer

The Answer of  The index of refraction is related to the prism angle and the angle of minimum deviation by n = sin ½($\delta$ + $\phi$ )/sin ½$\phi$ 
The angle of minimum deviation in the figure is angle
A) 1 
B) 2 
C) 3 
D) 4 
E) 5

The Index of Refraction Is Related to the Prism Angle δ\deltaδ

The Index of Refraction Is Related to the Prism Angle $\delta$