A light wave traveling in air impinges on an amber plate at an angle of incidence of 60º.If the angle of refraction is 34º,the velocity of light in amber must be approximately A)0.52 $\times$ 10⁸ m/s B)4.64 $\times$ 10⁸ m/s C)1.86 $\times$ 10³ m/s D)2.09 $\times$ 10⁸ m/s E)4.64 $\times$ 10¹⁰ m/s

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Snell's law: n1 sin θ1 = n2 sin θ2n1 = 1 (air)n2 = ? (amber)θ1 = 60ºθ2 = 34ºn2 = n1 sin θ1 / sin θ2n2 = 1 * sin 60º / sin 34ºn2 ≈ 1.86v = c / nv = 3 * 10^8 m/s / 1.86v ≈ 1.61 * 10^8 m/s

A Light Wave Traveling in Air Impinges on an Amber ×\times×

A Light Wave Traveling in Air Impinges on an Amber $\times$