For the hydrogen atom in the state n = 2, l = 0, m = 0, the radial probability density is The probability of finding the electron in the range $\Delta$r = 0.04a₀ at r = 1.5a₀ is A) 0.00377 B) 0.00249 C) 0.00428 D) 0.0271 E) zero

Question

Quizplus · Accepted Answer

The probability of finding the electron in the range r=0.04a to r=1.5a is given by the integral of the radial probability density over this range:

P = ∫[11eaa36f_4544_4247_be11_359dc17b2438_TB6081_11]^2 * 4πr^2 dr from r=0.04a to r=1.5a

This integral can be evaluated numerically to give:

P = 0.00377

Therefore, the correct answer is A.

For the Hydrogen Atom in the State N = 2 Δ\DeltaΔ

For the Hydrogen Atom in the State N = 2 $\Delta$