The half-life of phosphorus-32 is 14.3 d.If you have 1.00 g of phosphorous-32 today,the amount remaining in 10 d will be approximately
A)700 mg
B)650 mg
C)616 mg
D)384 mg
E)350 mg

Question

Quizplus · Accepted Answer

The half-life formula is used to calculate the remaining amount of a substance after a certain time period. The formula is: remaining amount = initial amount * (1/2)^(time/half-life). For phosphorus-32 with a half-life of 14.3 days, after 10 days, the remaining amount = 1.00 g * (1/2)^(10/14.3) ≈ 0.616 g, or 616 mg.

The Half-Life of Phosphorus-32 Is 14