If,on the average,each fission reaction of ²³⁵U releases 200 MeV of energy,how many nuclei of ²³⁵U fission every second in a 200-MW reactor? A)6.3 $\times$ 10¹⁸ B)6.0 $\times$ 10²³ C)1.0 $\times$ 10¹⁹ D)1.6 $\times$ 10¹⁹ E)2.7 $\times$ 10¹⁸

Question

Quizplus · Accepted Answer

The correct answer is A.The energy released by each fission reaction is 200 MeV, which is equal to 3.2 × 10^-11 J. The power of the reactor is 200 MW, which is equal to 2 × 10^8 J/s. Therefore, the number of nuclei of 235U fission every second is:2 × 10^8 J/s / (3.2 × 10^-11 J/fission) = 6.3 × 10^18 fissions/s

If,on the Average,each Fission Reaction of 235U Releases 200 MeV ×\times×

If,on the Average,each Fission Reaction of ²³⁵U Releases 200 MeV $\times$