The energy of a cosmic ray is given by $\gamma$mc², where m is the mass of the particle, c is the speed of light, and$\gamma$ is the Lorentz factor and . If a cosmic ray proton is traveling at a speed of $\nu$= 0.999999c, what is its energy? How does that compare to the kinetic energy of a grape thrown up in the air and caught in your mouth? Assume the grape has a mass of about 5 grams and a speed of 0.5 m/s when you catch it. The mass of a proton is 1.7 * 10^-27 kg.

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The Answer of The energy of a cosmic ray is given by $\gamma$mc², where m is the mass of the particle, c is the speed of light, and$\gamma$ is the Lorentz factor and . If a cosmic ray proton is traveling at a speed of $\nu$= 0.999999c, what is its energy? How does that compare to the kinetic energy of a grape thrown up in the air and caught in your mouth? Assume the grape has a mass of about 5 grams and a speed of 0.5 m/s when you catch it. The mass of a proton is 1.7 * 10^-27 kg.

The Energy of a Cosmic Ray Is Given By γ\gammaγ Mc2, Where M Is the Mass of the Particle, C

The Energy of a Cosmic Ray Is Given By $\gamma$ Mc², Where M Is the Mass of the Particle, C