Let $f ( t ) = \left\{ \begin{array} { l l }
1 & \text { if } 0 \leq t \leq 3 \
t - 2 & \text { if } t 3
\end{array} \right\}$ . Then $\mathcal { L } \{ f ( t ) \}$ is
A) $1 / s - e ^ { - 3 s } / s ^ { 2 }$
B) $1 / s + e ^ { 3 s } / s$
C) $1 / s + e ^ { - 3 s } / s$
D) $1 / s + e ^ { 3 s } / s ^ { 2 }$
E) $1 / s + e ^ { - 3 s } / s ^ { 2 }$

Question

Let $f ( t ) = \left\{ \begin{array} { l l } 
1 & \text { if } 0 \leq t \leq 3 \
t - 2 & \text { if } t > 3
\end{array} \right\}$ . Then $\mathcal { L } \{ f ( t ) \}$ is
A) $1 / s - e ^ { - 3 s } / s ^ { 2 }$
B) $1 / s + e ^ { 3 s } / s$
C) $1 / s + e ^ { - 3 s } / s$
D) $1 / s + e ^ { 3 s } / s ^ { 2 }$
E) $1 / s + e ^ { - 3 s } / s ^ { 2 }$

Quizplus · Accepted Answer

The Answer of Let $f ( t ) = \left\{ \begin{array} { l l } 
1 & \text { if } 0 \leq t \leq 3 \
t - 2 & \text { if } t > 3
\end{array} \right\}$ . Then $\mathcal { L } \{ f ( t ) \}$ is
A) $1 / s - e ^ { - 3 s } / s ^ { 2 }$
B) $1 / s + e ^ { 3 s } / s$
C) $1 / s + e ^ { - 3 s } / s$
D) $1 / s + e ^ { 3 s } / s ^ { 2 }$
E) $1 / s + e ^ { - 3 s } / s ^ { 2 }$

Let f(t)={1 if 0≤t≤3t−2 if t>3}f ( t ) = \left\{ \begin{array} { l l } 1 & \text { if } 0 \leq t \leq 3 \\t - 2 & \text { if } t > 3\end{array} \right\}f(t)={1t−2​ if 0≤t≤3 if t>3​}

Let $f ( t ) = \left\{ \begin{array} { l l } 1 & \text { if } 0 \leq t \leq 3 \\t - 2 & \text { if } t > 3\end{array} \right\}$