In the previous problem, the amount of chemical $C , X ( t )$ , produced by time t is
A) $x = 800 \left( 1 - e ^ { - 400 k t } \right) / \left( 2 - e ^ { - 400 k t } \right) , \text { where } k = \ln ( 29 / 26 ) / 4000$
B) $x = 800 \left( 1 - e ^ { - 800 k t } \right) / \left( 4 - e ^ { - 800 k t } \right) , \text { where } k = \ln ( 29 / 20 ) / 8000$
C) $x = 400 \left( 1 - e ^ { - 800 k t } \right) / \left( 4 - e ^ { - 800 k t } \right) , \text { where } k = \ln ( 29 / 20 ) / 8000$
D) $x = 400 \left( 1 - e ^ { - 400 k t } \right) / \left( 4 - e ^ { - 400 k t } \right) , \text { where } k = \ln ( 29 / 26 ) / 4000$
E) $x = 600 \left( 1 - e ^ { - 800 k t } \right) / \left( 4 - e ^ { - 800 k t } \right) , \text { where } k = \ln ( 29 / 20 ) / 8000$

Question

Quizplus · Accepted Answer

The correct formula for the amount of chemical $C, X(t)$, is given by $x = 800 \left( 1 - e ^ { - 400 k t } \right) / \left( 2 - e ^ { - 400 k t } \right)$, where $k = \ln ( 29 / 26 ) / 4000$. This formula correctly accounts for the exponential growth behavior of the chemical concentration over time, with $k$ representing the growth rate constant calculated based on given parameters.

In the Previous Problem, the Amount of Chemical C,X(t)C , X ( t )C,X(t)

In the Previous Problem, the Amount of Chemical $C , X ( t )$