To be metabolized, glucose must be converted to glucose 6-phosphate. However, at equilibrium, a mixture of glucose and phosphate at concentrations that exist in cells would contain little glucose 6-phosphate. How do cells circumvent this problem?
A) An enzyme lowers the activation energy barrier to favor glucose 6-phosphate formation.
B) An enzyme changes the equilibrium constant for the reaction to favor glucose 6-phosphate formation.
C) ATP, rather than phosphate, is used as the donor of the phosphoryl group, and the formation of glucose 6-phosphate is endergonic.
D) ATP, not Pi, is used as the donor of the phosphoryl group, and, thus, the formation of glucose 6-phosphate is exergonic.
E) Phosphate from the hydrolysis of ATP is used to phosphorylate glucose.
Correct Answer:
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