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Suppose you have a population of flour beetles with 1,000 individuals. Normally the beetles are red; however, this population is polymorphic for a mutant autosomal body color, black, designated by b/b. Red is dominant to black, so B/B and B/b genotypes are red. Assume the population is in Hardy-Weinberg equilibrium, with equal frequencies of the two alleles.
-What would be the expected red and black allele frequencies if 1000 black individuals migrated into the population?
A) 0.75 red; 0.25 black
B) 0.25 red; 0.75 black
C) 0.33 red; 0.67 black
D) They would not change because the population would still be in Hardy-Weinberg equilibrium.
E) None of the above

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Quizplus · Accepted Answer

When 1000 black individuals migrate into the population, the frequency of the b allele increases. Using the Hardy-Weinberg equation, we can calculate the new allele frequencies:
p^2 + 2pq + q^2 = 1
Assuming the red allele is p and the black allele is q, and the initial frequency of both alleles is 0.5, we can solve for q^2:
q^2 = (1000)/(2000) = 0.5
So q = 0.5, and p = 0.5.
Since red is dominant, we can calculate the expected frequencies of red and black individuals:
Red: p^2 + 2pq = (0.5)^2 + 2(0.5)(0.5) = 0.75 or 75%
Black: q^2 = (0.5)^2 = 0.25 or 25%
Therefore, the expected allele frequencies are 0.25 for the black allele and 0.75 for the red allele. The correct answer is B.

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