The frequency of A alleles is 0.2. The frequency of heterozygotes for this allele is
A) 0.8.
B) 0.4.
C) 0.16.
D) 0.32.
E) 0.08.

Question

Quizplus · Accepted Answer

If the frequency of A alleles is 0.2, then the frequency of a alleles must be 0.8 (since these are the only two possible alleles in this scenario).
Assuming that the population is in Hardy-Weinberg equilibrium, we can use the equation p^2 + 2pq + q^2 = 1, where p is the frequency of the A allele and q is the frequency of the a allele. In this case, p = 0.2 and q = 0.8. 
So, substituting these values into the equation, we get:
(0.2)^2 + 2(0.2)(0.8) + (0.8)^2 = 1
0.04 + 0.32 + 0.64 = 1
Therefore, the frequency of heterozygotes (2pq) is 0.32, which corresponds to choice D.

The Frequency of a Alleles Is 0