If the distance of a galaxy is 100 Mly,what is its recessional velocity if the Hubble constant is 22 km/s/Mly?
A) 100 km/s
B) 220 km/s
C) 1,000 km/s
D) 2,200 km/s

Question

Quizplus · Accepted Answer

Using Hubble's law, recession velocity (v) = H0 x d, where H0 is the Hubble constant and d is the distance to the galaxy. 
v = 22 km/s/Mly x 100 Mly = 2200 km/s. 
Therefore, the correct option is D).

If the Distance of a Galaxy Is 100 Mly,what Is