The Height (In Meters) of a Projectile Shot Vertically Upward $2.5$

The height (in meters) of a projectile shot vertically upward from a point $2.5$ m above ground level with an initial velocity of 25.48 m/s is $h = 2.5 + 25.48 t - 4.9 t ^ { 2 }$ after t seconds.
a. When does the projectile reach its maximum height?
b. What is the maximum height?

A) $$2.8 \mathrm {~s}$$
$34.428 \mathrm {~m}$
B) $2 \mathrm {~s}$
$32.86 \mathrm {~m}$
C) $2.38$
$34.183 \mathrm {~m}$
D) $$2.4 s$$
$34.428 \mathrm {~m}$
E) $$2.6 \mathrm {~s}$$
$35.624 \mathrm {~m}$