A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every $20 \text { minutes }$ . The initial population of a culture is $25$ cells. Find the number of cells after $6$ hours.
A) $P = 6,673,600$
B) $P = 6,553,600$
C) $P = 6,653,600$
D) $P = 6,565,600$
E) $P = 6,693,600$

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The Answer of A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every $20 \text { minutes }$ . The initial population of a culture is $25$ cells. Find the number of cells after $6$ hours.
A) $P = 6,673,600$
B) $P = 6,553,600$
C) $P = 6,653,600$
D) $P = 6,565,600$
E) $P = 6,693,600$

A Common Inhabitant of Human Intestines Is the Bacterium Escherichia 20 minutes 20 \text { minutes }20 minutes

A Common Inhabitant of Human Intestines Is the Bacterium Escherichia $20 \text { minutes }$