Set up, but do not evaluate, an integral for the length of the curve. $y=2 e^{x} \sin x, \quad \quad 0 \leq x \leq \frac{9 \pi}{2}$
A) $L=\int_{0}^{9 x / 2} \sqrt{1-4 e^{2 x}(1+\sin 2 x)} d x$
B) $L=\int_{0}^{9 x / 2} \sqrt{1+4 e^{2 x}(1-\sin x)} d x$
C) $L=\int_{0}^{9 x / 2} \sqrt{1-4 e^{2 x}(1-\sin 2 x)} d x$
D) $L=\int_{0}^{9 x / 2} \sqrt{1+4 e^{2 x}(1-\sin 2 x)} d x$
E) $L=\int_{0}^{9 x / 2} \sqrt{1+4 e^{2 x}(1+\sin 2 x)} d x$

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The Answer of Set up, but do not evaluate, an integral for the length of the curve. $y=2 e^{x} \sin x, \quad \quad 0 \leq x \leq \frac{9 \pi}{2}$
A) $L=\int_{0}^{9 x / 2} \sqrt{1-4 e^{2 x}(1+\sin 2 x)} d x$
B) $L=\int_{0}^{9 x / 2} \sqrt{1+4 e^{2 x}(1-\sin x)} d x$
C) $L=\int_{0}^{9 x / 2} \sqrt{1-4 e^{2 x}(1-\sin 2 x)} d x$
D) $L=\int_{0}^{9 x / 2} \sqrt{1+4 e^{2 x}(1-\sin 2 x)} d x$
E) $L=\int_{0}^{9 x / 2} \sqrt{1+4 e^{2 x}(1+\sin 2 x)} d x$

Set Up, but Do Not Evaluate, an Integral for the Length