Use Simpson's Rule to approximate the integral with answers rounded to four decimal places. $\int_{0}^{\pi / 2} \sqrt{2+\sin ^{2} x} d x ; \quad n=6$
A) 2.2028
B) 2.7519
C) 3.0265
D) 2.4774

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The Answer of Use Simpson's Rule to approximate the integral with answers rounded to four decimal places. $\int_{0}^{\pi / 2} \sqrt{2+\sin ^{2} x} d x ; \quad n=6$
A) 2.2028
B) 2.7519
C) 3.0265
D) 2.4774

Use Simpson's Rule to Approximate the Integral with Answers Rounded ∫0π/22+sin⁡2xdx;n=6\int_{0}^{\pi / 2} \sqrt{2+\sin ^{2} x} d x ; \quad n=6∫0π/2​2+sin2x​dx;n=6

Use Simpson's Rule to Approximate the Integral with Answers Rounded $\int_{0}^{\pi / 2} \sqrt{2+\sin ^{2} x} d x ; \quad n=6$