What is the escape velocity from Mars if its mass is 6 × 10²³ kg and its radius is 3,400 km? A)2,400 m/s B)4,900 m/s C)8,600 km/s D)12,000 m/s E)25,000 km/s

Question

Quizplus · Accepted Answer

Escape velocity can be calculated using the formula:

v = √(2GM / r)

where:
G is the gravitational constant (6.67 × 10^-11 Nm^2/kg^2)
M is the mass of the planet
r is the radius of the planet

Plugging in the values for Mars, we get:

v = √(2(6.67 × 10^-11 Nm^2/kg^2)(6 × 10^23 kg) / 3,400,000 m)
v ≈ 4,900 m/s

Therefore, the escape velocity from Mars is about 4,900 m/s, which corresponds to choice B.

What Is the Escape Velocity from Mars If Its Mass