Exhibit 5-9.On a particular production line,the likelihood that a light bulb is defective is 5%.Ten light bulbs are randomly selected. Refer to Exhibit 5-9.What is the probability that two light bulbs will be defective?
A)0.0105
B)0.0746
C)0.3151
D)0.5987

Question

Quizplus · Accepted Answer

The probability of exactly two defective light bulbs in a sample of ten can be calculated using the binomial probability formula: P(X=k) = C(n,k) * p^k * (1-p)^(n-k), where n=10, k=2, and p=0.05. This calculation results in approximately 0.0746.