Use mathematical induction to prove that the formula $1 \cdot 3 + 2 \cdot 4 + 3 \cdot 5 + \cdots + n ( n + 2 ) = \frac { n ( n + 1 ) ( 2 n + 7 ) } { 6 }$ is true for all natural numbers $n$ .

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The Answer of Use mathematical induction to prove that the formula $1 \cdot 3 + 2 \cdot 4 + 3 \cdot 5 + \cdots + n ( n + 2 ) = \frac { n ( n + 1 ) ( 2 n + 7 ) } { 6 }$ is true for all natural numbers $n$ .

Use Mathematical Induction to Prove That the Formula 1⋅3+2⋅4+3⋅5+⋯+n(n+2)=n(n+1)(2n+7)61 \cdot 3 + 2 \cdot 4 + 3 \cdot 5 + \cdots + n ( n + 2 ) = \frac { n ( n + 1 ) ( 2 n + 7 ) } { 6 }1⋅3+2⋅4+3⋅5+⋯+n(n+2)=6n(n+1)(2n+7)​

Use Mathematical Induction to Prove That the Formula $1 \cdot 3 + 2 \cdot 4 + 3 \cdot 5 + \cdots + n ( n + 2 ) = \frac { n ( n + 1 ) ( 2 n + 7 ) } { 6 }$