A Triumph sports car starts at rest and accelerates uniformly to a speed of 27.0 m/s in 11.8 s.Calculate the distance the car travels during this time interval.
A)160 m
B)320 m
C)1.90 km
D)640 m
E)350 m

Question

Quizplus · Accepted Answer

The distance traveled by the car can be calculated using the formula for uniform acceleration: $d = v_i t + \frac{1}{2} a t^2$, where $d$ is the distance, $v_i$ is the initial velocity (0 m/s in this case), $t$ is the time (11.8 s), and $a$ is the acceleration. First, we find the acceleration: $a = \frac{\Delta v}{t} = \frac{27.0\, \text{m/s}}{11.8\, \text{s}} = 2.29\, \text{m/s}^2$. Then, we calculate the distance: $d = 0 + \frac{1}{2} \times 2.29 \times (11.8)^2 = 159.6\, \text{m}$, which rounds to 160 m.

A Triumph Sports Car Starts at Rest and Accelerates Uniformly