The tension in the left-hand string in terms of $\theta$₁, $\theta$₂, and m is A) mg $\times$ cos $\theta$₁ / (sin $\theta$₁ sin $\theta$₂ + cos $\theta$₁ cos $\theta$₂) B) mg $\times$ sin $\theta$₂ / (sin $\theta$₁ sin $\theta$₂ + cos $\theta$₁ cos $\theta$₂) C) mg $\times$ cos $\theta$₂ / (sin $\theta$₁ sin $\theta$₂ + cos $\theta$₁ cos $\theta$₂) D) mg $\times$ cos $\theta$₂ / (sin $\theta$₁ cos $\theta$₂ + cos $\theta$₁ sin $\theta$₂)

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The Answer of The tension in the left-hand string in terms of $\theta$₁, $\theta$₂, and m is A) mg $\times$ cos $\theta$₁ / (sin $\theta$₁ sin $\theta$₂ + cos $\theta$₁ cos $\theta$₂) B) mg $\times$ sin $\theta$₂ / (sin $\theta$₁ sin $\theta$₂ + cos $\theta$₁ cos $\theta$₂) C) mg $\times$ cos $\theta$₂ / (sin $\theta$₁ sin $\theta$₂ + cos $\theta$₁ cos $\theta$₂) D) mg $\times$ cos $\theta$₂ / (sin $\theta$₁ cos $\theta$₂ + cos $\theta$₁ sin $\theta$₂)

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The Tension in the Left-Hand String in Terms Of $\theta$ ₁ $\theta$