A bullet with a mass of 12 g moving horizontally strikes a fixed block of wood and penetrates a distance of 5.2 cm.The speed of the bullet just before the collision is 640 m/s.The average force that the wood exerted on the bullet was A)4.7 $\times$ 10⁴ N B)74 N C)4.7 $\times$ 10⁶ N D)unknown; the mass of the wood is required E)None of these is correct.

Question

Quizplus · Accepted Answer

The average force can be calculated using the work-energy principle. The work done by the force is equal to the change in kinetic energy of the bullet. The initial kinetic energy is (1/2)mv^2, and the final kinetic energy is 0. The work done is also equal to force times distance. Solving for force gives approximately 4.7 x 10^4 N.

A Bullet with a Mass of 12 G Moving Horizontally ×\times×

A Bullet with a Mass of 12 G Moving Horizontally $\times$