Two forces,both of magnitude 12 N and directed 35 degrees either side of the direction of motion,pull a crate 15 m.How much work is done by the forces in moving the crate? A)1.8 $\times$ 10² J B)1.5 $\times$ 10² J C)2.9 $\times$ 10² J D)2.9 $\times$ 10² N/m E)2.1 $\times$ 10² J

Question

Quizplus · Accepted Answer

The resultant force in the direction of motion can be found by adding the horizontal components of the two forces. Each force has a horizontal component of $12 \cos(35^\circ)$ N. Therefore, the total force in the direction of motion is $2 \times 12 \cos(35^\circ)$ N. Work done is the product of this force and the distance (15 m) moved in the direction of the force. Thus, the work done is $2 \times 12 \cos(35^\circ) \times 15$ J, which calculates to approximately 2.1 kJ, making option E the correct answer.

Two Forces,both of Magnitude 12 N and Directed 35 Degrees ×\times×

Two Forces,both of Magnitude 12 N and Directed 35 Degrees $\times$