A car having a total mass of 2250 kg and traveling at 72.0 km/h smashes into a tree.The car is stopped in 0.250 s.The average force acting on the car during the collision is A)1.80 $\times$ 10⁵ N B)80.0 N C)1.80 $\times$ 10² N D)zero E)2.20 $\times$ 10⁴ N

Question

Quizplus · Accepted Answer

The average force acting on the car during the collision is equal to the change in momentum divided by the time interval:$$F = \frac{mv_f - mv_i}{t}$$where:* F is the average force (in newtons)* m is the mass of the car (in kilograms)* v_f is the final velocity of the car (in meters per second)* v_i is the initial velocity of the car (in meters per second)* t is the time interval (in seconds)In this case, the car has a mass of 2250 kg, an initial velocity of 72.0 km/h (which is equal to 20.0 m/s), a final velocity of 0 m/s, and a time interval of 0.250 s. Plugging these values into the equation, we get:$$F = \frac{(2250 	ext{ kg})(0 	ext{ m/s}) - (2250 	ext{ kg})(20.0 	ext{ m/s})}{0.250 	ext{ s}}$$$$F = -1.80 	imes 10^5 	ext{ N}$$The negative sign indicates that the force is acting in the opposite direction of the car's motion. Therefore, the average force acting on the car during the collision is 1.80 × 10^5 N.

A Car Having a Total Mass of 2250 Kg and Traveling