A particle of unknown mass has a momentum of 73 kg · m/s.At a time 7.3 s later,the momentum of the particle is 38 kg · m/s.What is the magnitude of the force acting on the particle during the interval,assuming the motion is in a straight line?
A)It cannot be determined because the mass of the particle is not given.
B)4.8 N
C)10 N
D)5.3 N
E)9.4 N

Question

Quizplus · Accepted Answer

The force acting on the particle can be calculated using the change in momentum (impulse) and the time interval. The change in momentum is the final momentum minus the initial momentum, which is 38 kg·m/s - 73 kg·m/s = -35 kg·m/s. The time interval is 7.3 s. The force is then calculated using the formula F = Δp/Δt, where Δp is the change in momentum and Δt is the time interval. So, F = -35 kg·m/s / 7.3 s = -4.79 N, which is approximately 4.8 N in magnitude. The negative sign indicates the direction of the force, but the question asks for the magnitude, so we take the absolute value.

A Particle of Unknown Mass Has a Momentum of 73