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Use the Picture to the Right to Answer the Next α\alpha

Question 72

Multiple Choice

Use the picture to the right to answer the next question. A puck of m1 and moving with velocity v1 collides elastically with a second puck of mass m2, which is initially at rest. After the collision, m1 moves with velocity v1’ at an angle α below the x axis and m2 moves with velocity v2’ at an angle θ above the x axis.
 Use the picture to the right to answer the next question. A puck of m<sub>1</sub> and moving with velocity v<sub>1</sub> collides elastically with a second puck of mass m<sub>2</sub>, which is initially at rest. After the collision, m<sub>1</sub> moves with velocity v<sub>1</sub>’ at an angle α below the x axis and m<sub>2</sub> moves with velocity v<sub>2</sub>’ at an angle θ above the x axis.   -The conservation of momentum along the x direction can be written as A) m<sub>1</sub> v<sub>1</sub> = m<sub>1</sub>v<sub>1</sub>' cos  \alpha  + m<sub>2</sub>v<sub>2</sub>' cos  \theta  B) 0 = m<sub>1</sub>v<sub>1</sub>' cos  \alpha  + m<sub>2</sub>v<sub>2</sub>' cos  \theta  C) m<sub>1</sub> v<sub>1</sub> = m<sub>1</sub>v<sub>1</sub>' sin  \alpha   + m<sub>2</sub>v<sub>2</sub>' sin  \theta  D) 0 = m<sub>1</sub>v<sub>1</sub>' sin  \alpha  + m<sub>2</sub>v<sub>2</sub>' sin  \theta  E) none of the above
-The conservation of momentum along the x direction can be written as


A) m1 v1 = m1v1' cos α\alpha + m2v2' cos θ\theta
B) 0 = m1v1' cos α\alpha + m2v2' cos θ\theta
C) m1 v1 = m1v1' sin α\alpha + m2v2' sin θ\theta
D) 0 = m1v1' sin α\alpha + m2v2' sin θ\theta
E) none of the above

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