A uniform stick 1 m long is placed horizontally on the ground along an east-west axis.A force of 1.0 N is applied to the center of the stick in a direction 30º west of north.The torque exerted by the force relative to the east end of the stick is
A)zero.
B)0.25 m,clockwise.
C)0.43 m,clockwise.
D)0.25 m,counterclockwise.
E)0.43 m,counterclockwise.

Question

Quizplus · Accepted Answer

The torque is given by the formula:

τ = F d sin θ

where F is the force applied, d is the distance from the axis of rotation to the line of action of the force, and θ is the angle between the force and the line joining the axis of rotation to the point of application of the force.

In this case, F = 1 N, d = 0.5 m (since the force is applied at the center of the 1 m long stick), and θ = 60º (since the force is 30º west of north, which makes an angle of 60º with the east-west axis).

Plugging these values into the formula, we get:

τ = (1 N)(0.5 m)(sin 60º) = 0.433 Nm clockwise

So the answer is (C) 0.43 m clockwise.

A Uniform Stick 1 M Long Is Placed Horizontally on the Ground