A 1.00 m string fixed at both ends vibrates in its fundamental mode at 440 Hz.What is the speed of the waves on this string?
A)220 m/s
B)440 m/s
C)660 m/s
D)880 m/s
E)1.10 km/s

Question

Quizplus · Accepted Answer

The speed of the waves on the string can be calculated using the formula for the fundamental frequency of a string fixed at both ends: $f = \frac{v}{2L}$, where $f$ is the frequency, $v$ is the speed of the wave, and $L$ is the length of the string. Rearranging for $v$, we get $v = 2Lf$. Substituting $L = 1.00 m$ and $f = 440 Hz$, we get $v = 2 \times 1.00 m \times 440 Hz = 880 m/s$.

A 100 M String Fixed at Both Ends Vibrates in Its