For a tube of length 57.0 cm that is open at both ends,what is the frequency of the fundamental mode? (the speed of sound in air is 340 m/s)
A)149 Hz
B)447 Hz
C)596 Hz
D)298 Hz
E)746 Hz

Question

Quizplus · Accepted Answer

The fundamental frequency for a tube open at both ends is given by $ f = \frac{v}{2L} $, where $ v $ is the speed of sound and $ L $ is the length of the tube. Substituting $ v = 340 \, \text{m/s} $ and $ L = 0.57 \, \text{m} $, we get $ f = \frac{340}{2 \times 0.57} \approx 298 \, \text{Hz} $.

For a Tube of Length 57