What mass of He gas occupies 8.5 liters at 0 $\circ$ C and 1 atmosphere? (The molar mass of He = 4.00 g/mol.)
A)10.5 g
B)0.66 g
C)2.6 g
D)0.38 g
E)1.52 g

Question

Quizplus · Accepted Answer

To find the mass of He gas, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Given that the volume V = 8.5 liters, P = 1 atmosphere, and T = 0°C (which is 273.15 K), we can solve for n, the number of moles of He. The ideal gas constant R = 0.0821 L·atm/(mol·K). Rearranging the ideal gas law to solve for n gives n = PV/(RT). Substituting the given values, n = (1 atm * 8.5 L) / (0.0821 L·atm/(mol·K) * 273.15 K) = 0.379 moles of He. The mass of He can then be found by multiplying the number of moles by the molar mass of He (4.00 g/mol), so the mass = 0.379 moles * 4.00 g/mol = 1.52 g.

What Mass of He Gas Occupies 8 ∘\circ∘ C and 1 Atmosphere? (The Molar Mass of He =

What Mass of He Gas Occupies 8 $\circ$ C and 1 Atmosphere? (The Molar Mass of He =