Adding sodium amide (NaNH₂)to 1-butyne (CH₃CH₂C≡CH)would produce: A)CH₃CH₂C≡CNa + NH₃ B)CH₃CH₂C≡C-C≡CH₂CH₃ + NaH + NH₃ C)CH₃CH₂C≡CNH₂ + NaH D)NaCH₂CH₂C≡CH + NH₃ E)CH₃CH(Na)C≡CH + NH₃

Question

Quizplus · Accepted Answer

Sodium amide (NaNH₂) is a strong base that deprotonates the terminal alkyne hydrogen in 1-butyne, forming the sodium acetylide (CH₃CH₂C≡CNa) and ammonia (NH₃).

Adding Sodium Amide (NaNH2)to 1-Butyne (CH3CH2C≡CH)would Produce

Adding Sodium Amide (NaNH₂)to 1-Butyne (CH₃CH₂C≡CH)would Produce