If 0.10 mol of HSCH₂CH₂OH reacts at 25 $\circ$ C,sequentially,with 0.20 mol of NaH,0.10 mol of CH₃CH₂Br followed by the addition of H₂O,which is the major product? A)HSCH₂CH₂OCH₂CH₃ B)CH₃CH₂SCH₂CH₂OH C)CH₃CH₂SCH₂CH₂OCH₂CH₃ D)CH₂=CH₂ E)CH₃CH₃

Question

Quizplus · Accepted Answer

The thiol group (HS-) in HSCH2CH2OH reacts with NaH to form a thiolate anion, which then reacts with CH3CH2Br to form CH3CH2SCH2CH2OH as the major product.

If 010 Mol of HSCH2CH2OH Reacts at 25 ∘\circ∘ C,sequentially,with 0

If 010 Mol of HSCH₂CH₂OH Reacts at 25^$\circ$C,sequentially,with 0