A compound that would show two triplets and a septet in the ¹H NMR spectrum could be:

Question

Quizplus · Accepted Answer

For a compound to show two triplets and a septet in its spectrum, it must have three different sets of chemically nonequivalent protons. The triplet and septet must be adjacent to each other in the proton environment, and the two triplets must be separated by a minimum of three bonds. 
Out of the given options, only chlorocyclopropane satisfies these requirements. It has three sets of nonequivalent protons: the two protons on the cyclopropane ring, the proton adjacent to the chlorine atom, and the three equivalent protons on the methyl group. The two triplets arise from the two protons on the ring and the proton adjacent to the chlorine atom, separated by a minimum of three bonds. The septet arises from the six protons on the ring and adjacent to the proton adjacent to the chlorine atom.

A Compound That Would Show Two Triplets and a Septet