A compound with the molecular formula C₁₀H₁₄gave the following ¹H NMR spectrum: doublet,$\delta$1.2 Singlet,$\delta$ 2.3 Septet,$\delta$ 2.8 Multiplet,$\delta$ 7.1 A possible structure for the compound is:

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The NMR spectrum shows the presence of three different types of proton environments: a doublet at 1.2 ppm, a singlet at 2.3 ppm, and a septet at 2.8 ppm. These signals are consistent with the proposed structure of compound II, where the two methyl groups on the thiophene ring give rise to the singlet and septet, and the proton on the cyclohexadiene ring gives rise to the doublet. The multiplet at 7.1 ppm is likely due to the aromatic protons on the thiophene and cyclohexadiene rings.

A Compound with the Molecular Formula C10H14 gave the Following δ\deltaδ

A Compound with the Molecular Formula C₁₀H₁₄gave the Following $\delta$