Briefly,but clearly,explain the following observation:
When 2-methylbutane reacts with Cl₂/h $v$ ,the monochlorinated products consist of four constitutional isomers in significant yields.However,when the same alkane is allowed to react with Br₂/ h $v$ ,there is only one major monobromination product.

Question

Briefly,but clearly,explain the following observation:
When 2-methylbutane reacts with Cl₂/h

v

,the monochlorinated products consist of four constitutional isomers in significant yields.However,when the same alkane is allowed to react with Br₂/ h

v

,there is only one major monobromination product.

Quizplus · Accepted Answer

The Answer of Briefly,but clearly,explain the following observation: When 2-methylbutane reacts with Cl₂/h$v$,the monochlorinated products consist of four constitutional isomers in significant yields.However,when the same alkane is allowed to react with Br₂/ h$v$,there is only one major monobromination product.

Briefly,but Clearly,explain the Following Observation: When 2-Methylbutane Reacts with Cl2/h vvv

Briefly,but Clearly,explain the Following Observation:
When 2-Methylbutane Reacts with Cl₂/h $v$