The ¹³C NMR spectrum of a compound with formula C₇H₁₄O gives three signals.Which of these structures is a possible one for this compound? A)2-Heptanone B)3-Heptanone C)2,2-Dimethyl-3-pentanone D)2,4-Dimethyl-3-pentanone E)Two of these choices.

Question

Quizplus · Accepted Answer

The NMR spectrum shows three signals, indicating the presence of three different types of protons. 
Structure A (2-Heptanone) has six different types of protons, and therefore should give more than three signals in the NMR spectrum. 
Structure B (3-Heptanone) has only two different types of protons and cannot give three distinct signals in the NMR spectrum. 
Structure C (2,2-Dimethyl-3-pentanone) has four different types of protons, and therefore cannot give three distinct signals in the NMR spectrum. 
Structure D (2,4-Dimethyl-3-pentanone) has three different types of protons and is consistent with the observed NMR spectrum. Therefore, the answer is D. 
Structure E is not a valid choice as it does not exist.

The 13C NMR Spectrum of a Compound with Formula C7H14O

The ¹³C NMR Spectrum of a Compound with Formula C₇H₁₄O