The scores on the Wechsler Adult Intelligence Scale are approximately Normal, with $\mu$ = 100 and $\sigma$ =15. If you scored 130, your score would be higher than approximately what percent of adults?
A)92%
B)95%
C)97.5%
D)99.7%

Question

Quizplus · Accepted Answer

To determine the percentage of adults scored below 130, we calculate the Z-score: $Z = \frac{X - \mu}{\sigma} = \frac{130 - 100}{15} = 2$. A Z-score of 2 corresponds to the 97.5th percentile in a normal distribution, meaning your score is higher than approximately 97.5% of adults.

The Scores on the Wechsler Adult Intelligence Scale Are Approximately μ\muμ

The Scores on the Wechsler Adult Intelligence Scale Are Approximately $\mu$