The produce manager for a local Sobey's store is interested in estimating the percentage of apples that arrive on a shipment with bruises. A random sample of 150 apples showed 14 with bruises. Based on this information, what is the margin of error for a 95 percent confidence interval estimate?
A) 0.0466
B) 0.0933
C) 0.0006
D) 0.0238
E) 0.0392

Question

Quizplus · Accepted Answer

The margin of error for a 95% confidence interval estimate is 0.0466. This is calculated using the formula:Margin of error = z * sqrt((p * (1-p)) / n)where:z is the z-score for the desired confidence level (95% = 1.96)p is the sample proportion of apples with bruises (14/150 = 0.0933)n is the sample size (150)Plugging these values into the formula, we get:Margin of error = 1.96 * sqrt((0.0933 * (1-0.0933)) / 150) = 0.0466

The Produce Manager for a Local Sobey's Store Is Interested