The conversion of glucose-6-phosphate to glucose-1-phosphate has a ΔG´° of + 8.4 kJ/mol. How can a reaction such as this proceed in a cell?
A) it must be coupled to ATP hydrolysis
B) the product must be rapidly used in a subsequent step of the pathway
C) it can only occur with the help of an enzyme
D) this reaction can not proceed and must go in the reverse manner
E) both B and C are correct

Question

Quizplus · Accepted Answer

The ΔG´° of +8.4 kJ/mol indicates that the reaction is not spontaneous under standard conditions. Therefore, the reaction must be coupled with another reaction that releases free energy, such as ATP hydrolysis or a subsequent step of the pathway. Additionally, the reaction requires an enzyme to facilitate the conversion of glucose-6-phosphate to glucose-1-phosphate. Thus, both options B and C are correct.

The Conversion of Glucose-6-Phosphate to Glucose-1-Phosphate Has a ΔG´° of