The association of a protein and a fragment of DNA has a ΔG°′ of -57 kJ/mol. What is the equilibrium constant at 25 °C for the formation of this complex? A) 1 B) -1 C) 10¹⁰ D) 10^-10 E) cannot be determined

Question

Quizplus · Accepted Answer

The equilibrium constant at 25°C can be calculated using the relationship: ΔG°' = -RTln(K_eq) where R is the gas constant and T is the temperature in Kelvin. Substituting the given values: -57 kJ/mol = -8.314 J/(mol K) x 298 K x ln(K_eq) Solving for K_eq: K_eq = e^(-57,000 J/mol / (8.314 J/(mol K) x 298 K)) = 2.1 x 10^9 The answer is therefore 10¹⁰.

The Association of a Protein and a Fragment of DNA