Find the area of the triangle with the vertices and . Round your answer to two decimal places.

Question

Find the area of the triangle with the vertices  and  . Round your answer to two decimal places.

Quizplus · Accepted Answer

Using the distance formula, we can find the length of two sides of the triangle: 
AB = $\sqrt{(1902-1901)^2 + (a696-a696)^2} = 1$ 
AC = $\sqrt{(63e5-63e5)^2 + (1902-1901)^2} = 1$ 
BC = $\sqrt{(63e5-63e5)^2 + (a696-a696)^2} = 0$

Since two sides have a length of 1 and the third side has a length of 0, the triangle degenerates to a line segment between points A and C. Therefore, the area of the triangle is 0. 
Rounding to two decimal places, we get 0.00, which corresponds to answer choice D.

Find the Area of the Triangle with the Vertices