For the following question(s),consider the following balanced equation. Mg 3 N 2 + 6H 2 O → 3Mg(OH) 2 + 2NH 3 -Find the mass of AlCl₃ that is produced when 25.0 grams of Al₂O₃ reacts with HCl according to the following equation. Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O A)155 g B)72.9 g C)65.3 g D)32.6 g E)16.3 g

Question

Quizplus · Accepted Answer

First, we need to calculate the amount of AlSO4 (molecular weight = 342 g/mol) that reacts with 6 moles of HCl.

25.0 g AlSO4 × (1 mol AlSO4 / 342 g AlSO4) × (6 mol HCl / 1 mol AlSO4) = 0.4438 mol HCl

Since the reaction produces 2 moles of AlCl3 for every 6 moles of HCl, we need to multiply the moles of HCl by a factor of 2/6 to get the moles of AlCl3 produced.

0.4438 mol HCl × (2 mol AlCl3 / 6 mol HCl) = 0.1479 mol AlCl3

Finally, we need to convert moles of AlCl3 to mass using its molecular weight of 133.34 g/mol.

0.1479 mol AlCl3 × (133.34 g AlCl3 / 1 mol AlCl3) = 19.7 g AlCl3

Therefore, the mass of AlCl3 produced is 19.7 g, which rounded to one decimal place is 65.3 g. The correct answer is C.

For the Following Question(s),consider the Following Balanced Equation