Barium chloride and sodium sulfate react according to the following equation.
BaCl2 + Na2SO4 → BaSO4 + 2NaCl
Answer the following question(s)about this reaction.
-How many grams of sodium chloride can be produced from 50.grams of barium chloride?
A)2.0 g
B)14 g
C)28 g
D)59 g
E)208 g

Question

Barium chloride and sodium sulfate react according to the following equation.
BaCl2 + Na2SO4 → BaSO4 + 2NaCl 
Answer the following question(s)about this reaction.
-How many grams of sodium chloride can be produced from 50.grams of barium chloride?
A)2.0 g
B)14 g
C)28 g
D)59 g
E)208 g

Quizplus · Accepted Answer

First, we need to calculate the molar mass of barium chloride (BaCl2) and sodium chloride (NaCl). The molar mass of BaCl2 is approximately 137.33 (Ba) + 2*35.45 (Cl) = 208.23 g/mol. The molar mass of NaCl is approximately 22.99 (Na) + 35.45 (Cl) = 58.44 g/mol. According to the balanced chemical equation, 1 mole of BaCl2 produces 2 moles of NaCl. Therefore, 50 grams of BaCl2 is equivalent to 50 g / 208.23 g/mol = 0.240 moles of BaCl2. This amount of BaCl2 will produce 0.240 moles * 2 = 0.480 moles of NaCl. Finally, converting moles of NaCl to grams: 0.480 moles * 58.44 g/mol = 28.05 grams of NaCl, which rounds to 28 grams.

Barium Chloride and Sodium Sulfate React According to the Following