It is an error to call the delete operator on a pointer a second time.Consider what happens if there is memory allocated on the free store for a class,a destructor,and initializing constructors have been defined,but no copy constructor was defined.Now suppose a function is called that has call-by-value parameters.Why does the program either die in the middle or give a segmentation fault?

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The Answer of It is an error to call the delete operator on a pointer a second time.Consider what happens if there is memory allocated on the free store for a class,a destructor,and initializing constructors have been defined,but no copy constructor was defined.Now suppose a function is called that has call-by-value parameters.Why does the program either die in the middle or give a segmentation fault?

It Is an Error to Call the Delete Operator on a Pointer