A 25.00 mL sample of hydrochloric acid solution, HCl, is titrated with 0.0512 M NaOH solution. The volume of NaOH solution required is 21.68 mL. What is the molarity of the HCl solution?
A)0.0444
B)0.0590
C)0.0295
D)0.0148

Question

Quizplus · Accepted Answer

The molarity of the HCl solution can be calculated using the titration formula: M1V1 = M2V2, where M1 and V1 are the molarity and volume of the HCl solution, and M2 and V2 are the molarity and volume of the NaOH solution. Rearranging the formula to solve for M1 gives M1 = (M2V2) / V1. Substituting the given values: M1 = (0.0512 M * 21.68 mL) / 25.00 mL = 0.0444 M.

A 2500 ML Sample of Hydrochloric Acid Solution, HCl, Is Titrated