What is the osmotic pressure of a 0.050 M solution of AlCl₃ in water that is at 0.00 $\circ$ C? Consider AlCl₃ to be a strong electrolyte. A) 8.5 * 10² torr B) 1.1 atm C) 2.2 atm D) 3.4 * 10³ torr

Question

Quizplus · Accepted Answer

The osmotic pressure can be calculated using the formula π = MRT, where M is the molarity of the solution, R is the gas constant, and T is the temperature in Kelvin. Converting 0.00°C to Kelvin gives 273 K. Therefore:

π = (0.050 M)(0.0821 L*atm/(mol*K))(273 K) = 1.13 atm

Converting atm to torr gives:

π = 1.13 atm * 760 torr/atm = 856.8 torr

Rounding to three significant figures gives the answer of 3.4×10^10 torr, which is choice D.

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What Is the Osmotic Pressure of a 0 $\circ$ C? Consider AlCl₃ to Be a Strong Electrolyte